Earl solved the following system of equation using substitution.
x + y = 3
2x - 3y = 16
Earl's Solution
2(3-y)-=16
6-y-3y=16
6-4y=16
6-6-4y=16-6
4y=10
-4y=10
-4= -4
y=-2.5
x+(-2.5)=3
x=5.5
Unfortunately, he made a mistake. Locate his error
Those 2 are both WRONG!!
The error is NOT with the "- 3y".
The "-" is there on Line 1, but the "3y" is missing. However, the "- 3y" was included on Line 2.
So, it was left out of one of the lines but wasn't forgotten, and was certainly included in the solution!
2(3-y)-=16 <==== Line 1
6-y-3y=16 <===== Line 2
6-4y=16 <======= Line 3
As seen above, the error was made in Line 2 as he DISTRIBUTED the 2 to the (3 - y), but got 6 - y instead of 6 - 2y. That's where the TRUE error lies!
That's all thatw's asked - to find the ERROR! Nothing else!!