SOLUTION: Let and be relatively prime integers with a > b > 0 and (a^3 - b^3)/(a-b)^3= 73/3. What is a-b?
Algebra.Com
Question 1160416: Let and be relatively prime integers with a > b > 0 and (a^3 - b^3)/(a-b)^3= 73/3. What is a-b?
Answer by greenestamps(13198) (Show Source): You can put this solution on YOUR website!
or
Then, since a and b are relatively prime integers with a > b > 0, a = 10 and b = 7.
And so a-b = 3.
ANSWER: a-b = 3
RELATED QUESTIONS
Let a not equal 0, b and c be integers with a and b relatively prime.
Show that if a|b*c (answered by venugopalramana)
Let a and b be relatively prime intergers and let k be any integer. Show that b and a+bk... (answered by richard1234)
Let a and b be positive integers, assume that (a^(3))|(b^(3)).
How do i prove tha a|b (answered by venugopalramana)
If A = {negative integers} and B = {positive integers}, what is A union B?
A.{0}... (answered by robertb)
Let a and b be complex numbers. If a + b = 4 and a^2 + b^2 = 6 + ab, then what is a^3 +... (answered by math_tutor2020,MathTherapy)
I do not even know where to start with this proof.
Prove or disprove: let a, b, and c... (answered by ikleyn)
let (a,b,c) be a primitive pythagorous triplet (a (answered by richard1234)
Two positive integers M and N are defined to be relatively prime if GCF(M, N) = 1.... (answered by consc198,math_iz_hard)
write each rational number in the form a/b where a and b are integers and b = 0.
a.)... (answered by stanbon)