SOLUTION: A chemical company makes two brands of antifreeze. The first brand is 65% pure antifreeze, and the second brand is 90% pure antifreeze. In order to obtain 110 gallons of a mixture

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Question 1145220: A chemical company makes two brands of antifreeze. The first brand is 65% pure antifreeze, and the second brand is 90% pure antifreeze. In order to obtain 110 gallons of a mixture that contains 70% pure antifreeze, how many gallons of each brand of antifreeze must be used?
Answer by ikleyn(52780)   (Show Source): You can put this solution on YOUR website!
.

x = gallons of the 90% mixture.


The equation


    0.65*(110-x) + 0.90x = 0.7*110


The solution is  x =  = 22 gallons.


ANSWER.  22 gallons of the 90% mixture and 110-22 = 88 gallons of the 65% mixture.


CHECK.  0.65*88 + 0.9*22 = 77 gallons of the pure antifreeze in ingredients, and

        0.7*110 = 77 gallons of the pure antifreeze in the final mixture.   ! Correct !

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It is a standard and typical mixture problem.

For introductory lessons covering various types of mixture word problems see
    - Mixture problems
    - More Mixture problems
    - Solving typical word problems on mixtures for solutions
    - Typical word problems on mixtures from the archive
in this site.

You will find there ALL TYPICAL mixture problems with different methods of solutions,
explained at different levels of detalization,  from very detailed to very short.

Read them and become an expert in solution mixture word problems.

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook in the section "Word problems" under the topic "Mixture problems".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.


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