SOLUTION: Solve the system by the method of elimination. (If there is no solution, enter NO SOLUTION. If the system is dependent, enter a for x and enter y in terms of a.)
1/2x+y=1/8
5/2
Algebra.Com
Question 1119622: Solve the system by the method of elimination. (If there is no solution, enter NO SOLUTION. If the system is dependent, enter a for x and enter y in terms of a.)
1/2x+y=1/8
5/2x+5y=5/8
(x,y)
Found 3 solutions by ankor@dixie-net.com, greenestamps, Alan3354:
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Solve the system by the method of elimination. (If there is no solution, enter NO SOLUTION. If the system is dependent, enter a for x and enter y in terms of a.)
:
cross multiply
2x + y = 8
:
cross multiply
5(2x+5y) = 5*8
10x + 25y = 40
simplify, divide by 5
2x + 5y = 8
This system has no solution
Answer by greenestamps(13198) (Show Source): You can put this solution on YOUR website!
Multiply the first equation by 5; the result is equal to the second equation.
Then solving the pair of equations by elimination (subtracting one equation from the other) results in the equation 0 = 0.
That equation is always true; the two equations are equivalent; they are different forms of the equation for the same straight line; the system of equations is dependent.
Of course, once you see that the first equation multiplied by 5 is the same as the second equation, you know that is the answer; there is no need to use elimination.
Then, according to the instructions, let x = a and solve for y in terms of a:
(1/2)a+y = 1/8
y = 1/8 - (1/2)a OR y = (1-4a)/8
The solutions are any ordered pair of the form (a, (1-4a)/8).
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
It's ambiguous.
Is it ?
Or ?
Or ?
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2 "solutions" are posted, with 2 different versions of your equation.
Making it clear and unambiguous is your responsibility, and it's important that you know how to do that.
====================
Parentheses are free, use some.
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In any case, the 2nd eqn is 5 times the 1st --> dependent.
An infinite # of solutions.
No unique solution.
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