SOLUTION: Given that the energy(e) varies directly as the resistance(r) and inversely as the square of the distance(d) if e=32/25, r=8 and d=5 a) calculate the constant k b) calculate r w

Question 1116932: Given that the energy(e) varies directly as the resistance(r) and inversely as the square of the distance(d) if e=32/25, r=8 and d=5
a) calculate the constant k
b) calculate r when e=16 and d=3
c) calculate d when r=5 and e=5/6

Found 3 solutions by solver91311, KMST, MathTherapy:
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!

So

The rest is just arithmetic

John

My calculator said it, I believe it, that settles it

Answer by KMST(5328)   (Show Source): You can put this solution on YOUR website!
If varies directly as and inversely as (the square of d),
the relation is
or , where is a constant.
You know that when and , .
Substituting those values into
,
you get
,
which you can solve for .

Now you know that the relation between , and ,
or between , and is
.

To calculate when and ,
you substitute the known values into ,
and solve for .

, and as you know is not a negative number,

.

When and , substituting into gives you

Answer by MathTherapy(10551)   (Show Source): You can put this solution on YOUR website!

Given that the energy(e) varies directly as the resistance(r) and inversely as the square of the distance(d) if e=32/25, r=8 and d=5
a) calculate the constant k
b) calculate r when e=16 and d=3
c) calculate d when r=5 and e=5/6

Correct answers:
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