SOLUTION: Can you please solve this equation using Cardano's method:
x^3+24x-25=0
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Question 1095189: Can you please solve this equation using Cardano's method:
x^3+24x-25=0
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
The general form for a cubic equation is
:
ax^3 + bx^2 + cx + d = 0
:
the problem's cubic equation is
:
x^3 + 24x - 25 = 0
:
this is a depressed cubic equation, the general form is x^3 + Ax = B
:
therefore we have
:
x^3 + 24x = 25
:
we determine s and t so that
:
1) 3st = A
2) s^3 - t^3 = B
:
Cardano's method tells us that x = s - t will be one of the roots of the cubic equation
:
Solving the equation 1 for s and substituting into equation 2, we get
:
(A/3t)^3 - t^3 = B
:
simplifying this we get
:
t^6 + Bt^3 - (A^3/27) = 0
:
let u = t^3, then we have a quadratic equation
:
u^2 + Bu - (A^3/27) = 0
:
referring to our depressed cubic equation, we need s and t to satisfy
:
3) 3st = 24
4) s^3 - t^3 = 25
:
u^2 +25u -(24^3/27) = 0
:
using quadratic formula, we have
:
u = (-25 + square root(25^2 - 4 * 1 * (-512))) / (2*1) = 13.3505
u = (-25 - square root(25^2 - 4 * 1 * (-512))) / (2*1) = -38.3505
:
we reject the negative solution for u, therefore
:
t^3 = 13.3505
s^3 = t^3 + 25 = 13.3505 + 25 = 38.3508
:
*****************************************************************************
x = (38.3505)^(1/3) - (13.3505)^(1/3) = 1.000000955 approximately 1
:
therefore one solution is x=1, the other two solutions are complex
:
(x-1)(x^2+x+25) = 0 = x^3 + 24x - 25
:
we see that the two solutions to x^2 + x + 25 = 0 (using quadratic formula) are
:
x = (1/2)(-1-3isquare root(11)
x = (1/2)(-1+3isquare root(11)
*****************************************************************************
:
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