SOLUTION: x^2+y^2-z^2=(x+y-z)^2+2 x^3+y^3-z^3=(x+y-z)^3+9 x^4+y^4-z^4=(x+y-z)^4+29 If the triple (x',y',x') is one of its solutions, calculate x'+y'+z'

SOLUTION: x^2+y^2-z^2=(x+y-z)^2+2 x^3+y^3-z^3=(x+y-z)^3+9 x^4+y^4-z^4=(x+y-z)^4+29 If the triple (x',y',x') is one of its solutions, calculate x'+y'+z'

Algebra.Com

Question 1090049: x^2+y^2-z^2=(x+y-z)^2+2
x^3+y^3-z^3=(x+y-z)^3+9
x^4+y^4-z^4=(x+y-z)^4+29
If the triple (x',y',x') is one of its solutions, calculate x'+y'+z'
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
x'+y'+z'=
x'+y'+z'=
RELATED QUESTIONS
y/4+z/4=z/3+x/3=x/2+y/2... (answered by ikleyn)

Solve {{{system(x+2*y-z = 5, 2*x-4*y+z = 0, 3*x+2*y+2*z = 3)}}} (answered by jim_thompson5910)

1/x + 2/y - 4/z = 1 2/x + 3/y + 8/z = 0 -1/x + 9/y + 10/z = 5 then solve x, y and... (answered by Fombitz)

If x=6, y=4, z=3, evaluate : x^-2 y^0 /... (answered by Mathtut)

find the ordered triple of these eqautions. x+y+z=8, x-y=2,... (answered by Alan3354)

solve for x,y and z 1. x+y-2z=5 2. x+z=4 3.... (answered by Alan3354)

Solve the system for x, y and z: x+y+z=8 x-y+z=2... (answered by Alan3354,TigerAlgebra)

if z=x+iy , z* conj(z)^3+conj(z)*z^3=350, then (x,y)=..[(2,1) ,(3,4) ,(4,3)... (answered by ikleyn)

If x : y = 3 : 2 and y : z = 5 : 4, find the ratio of x : y :... (answered by Boreal)