Solve both equations for
in terms of
Equation 1:
Equation 2:
Now that you have two expressions in
both equal to
, set the two expressions equal to each other:
The rational roots theorem tells us that if a rational root exists, it must be one of the following values:
Use Synthetic Division: (that the value 1 fails is left as an exercise for the student)
-1 | 1 -7 0 8
-1 8 -8
---------------------
1 -8 8 0
Hence,
and
are factors of the cubic.
Therefore one of the roots is -1 and the other two are the roots of the quadratic factor (calculation of these roots is left as an exercise for the student).
Using
with
One of the three points of intersection is
.
The other two are left for you to calculate.
John

My calculator said it, I believe it, that settles it
