SOLUTION: Jose and Eduardo are going to run a race. Jose is willing to give Eduardo a 3 mile head start. Jose runs at a rate of 7.5 miles per hour. Eduardo's rate is 1.5 miles per hour SLOWE

Question 1073991: Jose and Eduardo are going to run a race. Jose is willing to give Eduardo a 3 mile head start. Jose runs at a rate of 7.5 miles per hour. Eduardo's rate is 1.5 miles per hour SLOWER that Jose.
Found 2 solutions by josgarithmetic, ikleyn:
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
Eduardo's rate is 6 miles per hour. If he had the 3 mile head start, then for this distance he had run , half an hour.

d is the distance they both go when Jose catches up with Eduardo. t is how long it takes for Jose to reach Eduardo. SPEED TIME DISTANCE JOSE 7.5 t d EDUARDO 6 t+1/2 d

If solve for time only, t for how long to catchup,

-

-----catching-up time 2 hours

RACING DISTANCE d:
-

or

-
--------- 15 mile race
Answer by ikleyn(52803) (Show Source): You can put this solution on YOUR website!
.
Jose and Eduardo are going to run a race. Jose is willing to give Eduardo a 3 mile head start.
Jose runs at a rate of 7.5 miles per hour. Eduardo's rate is 1.5 miles per hour SLOWER that Jose.
~~~~~~~~~~~~~~~~~~~~~~~~~

Your equation is this: 7.5*t = 3 + 6*t The solution is 7.5t - 6t = 3, 1.5t = 3 ---> t = = 2 hours. Answer. Jose catches up Eduardo in 2 hours.

Writing by "josgarithmetic" (including his equation) is WRONG, NONSENSICAL and does not correspond to the condition..

It would be good (much better) if you put a question in your post.

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