4x + 10y = 48, (1) 10x + 4y = 36. (2) Multiply equation (1) by 5 (both sides). Multiply equation (2) by 2 (both sides). You will get 20x + 50y = 240, (3) 20x + 8y = 72. (4) Subtract eq(4) from eq(3) (both sides). You will get 42y = 240-72 = 168 ---> y == 4. Can you complete the solution from this point on your own ?
4x+10y = 48 (1) 10x+4y = 36 (2) Multiply both sides of (1) by 10, and both sides of (2) by 4: 40x + 100y = 480 (1') 40x + 16y = 144 (2') Subtract (2') from (1') to get: 0x + 84y = 336 —> y = 336/84 = 4. Using 4x + 10y = 48 and y=4 —> 4x + 10(4) = 48 —> 4x = 48-40 —> 4x = 8 —> x=2 — Ans:and — Check: 4(2) + 10(4) = 8 + 40 = 48 (ok, eqn 1 works) 10(2) + 4(4) = 20 + 16 = 36 (ok, eqn 2 works as well) —