SOLUTION: 300=10*a*x+49*x^2
400=(10*a+98*x)*y
300=(10*a+98*x)*z+49*z^2
3.134=x+y+z
Algebra.Com
Question 1070687: 300=10*a*x+49*x^2
400=(10*a+98*x)*y
300=(10*a+98*x)*z+49*z^2
3.134=x+y+z
Answer by ikleyn(52798) (Show Source): You can put this solution on YOUR website!
.
Sorry,
I do not understand for what reason did you submit your post to this site.
It is commonly accepted in this forum to ask question when you submit a problem.
It is not only commonly accepted . . . It is necessary . . . It is MANDATORY . . . It is REQUIRED by the RULES of this forum.
So, where is your question ? ( . . if you have it . . . )
Yet, we didn't learn to read the thoughts in your mind remotely.
We only can read what is written in your post.
So, again: what is your question ? ( . . . if you have it . . . )
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