= 90, (1) y = . (2) Square equation (2) (both sides). You will get = x. Using this, replace by "x" in the equation (2). You will get = 90, (1') or = 0. Solve by using the quadratic formula. You will get = = . Thus = 9, = -10. Since "x" under the square root must be non-negative, only the root x= 9 survives. Then y = = +/- 3. Answer. There are 2 solutions: (x,y) = (9,3) and (x,y) = (9,-3).