SOLUTION: Find a two digit number where the sum of the two digits is equal to fourteen and the ones digit is four more than the tens.

Question 1053775: Find a two digit number where the sum of the two digits is equal to fourteen and the ones digit is four more than the tens.
Found 2 solutions by jorel555, Shin123:
Answer by jorel555(1290) (Show Source): You can put this solution on YOUR website!
Let m be the first digit, and n be the second. Then:
m+n=14
m+4=n
So:
m+m+4=14
2m=10
m=5
n=9.
The number is 59. ☺☺☺☺
Answer by Shin123(626) (Show Source): You can put this solution on YOUR website!
So that means

☺☺☺
RELATED QUESTIONS
I the sum of the digits of a two digit number is 7 and the tens digit is one more than... (answered by Timnewman)
In a four digit number, the sum of the thousands and the hundreds digits is 3. The tens... (answered by ankor@dixie-net.com)
my tens digit is two more than my ones digit and four less than my hundreds digit the sum (answered by josgarithmetic)
The sum of the digits of a two digit number is 12. The ones digit is 2 more than the tens (answered by Edwin McCravy)
a two digit number is 5 times the sum of its digits and is also equal to 5 more than the... (answered by Theo)
The sum of the digits of a three-digit number is 13. The hundreds' digit is two more than (answered by vheroli)
In a three digit number, the hundreds digit is equal to the tens digit, and is two more... (answered by josgarithmetic)
This is a digit and coin word problem. I know how to do simpler digit and coin problems... (answered by Edwin McCravy)
The Sum of the digits of a two-digit number is 10. The ones digit is six more than the... (answered by oberobic)