| Solved by pluggable solver: SOLVE linear system by SUBSTITUTION |
| Solve: into another equation: Answer: |
You have two equations y = 3x - 5, (1) y = -2x - 15. (2) You just have "y" expressed via "x" in the equation (1): y 3x-5. Simply substitute it instead of "y" into the second equation. You will get 3x - 5 = -2x -15. (3) Now you have a single equation for one unknown "x" only. Simplify and solve it. I can express this procedure in other words. Sinse the left sides of the equations (1) and (2) are identical, their right sides are equal: 3x - 5 = -2x -15. (4) You get the sane equation as (3). Now simplify and solve it.