SOLUTION: find the point of intersection of x^2+y^2=25, x^2/18+ y^2/32=1

Question 1043924: find the point of intersection of x^2+y^2=25,
x^2/18+ y^2/32=1
Found 2 solutions by ikleyn, solver91311:
Answer by ikleyn(52798) (Show Source): You can put this solution on YOUR website!
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find the point of intersection of x^2+y^2=25,
x^2/18+ y^2/32=1
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= 25, (1) = 1. (2) Multiply (2) by 18 (both sides). You will get = 25, (1') = 18, (2') or equivalently = 25, (1'') = 18. (2'') Distract (2'') from (1''). You will get = 25 - 18, or = 7, or = 16. Hence, y = +/- 4. Then from (1) x = +/-3. Answer. There are four solution and, respectively, four intersection points: (x,y) = (3,4), (3,-4), (-3,-4), (-3, 4).

Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

You cannot find "the" point of intersection of the graphs of the two given equations. You can find a point of intersection, or you can find some of the points of intersection, or you can find all of the points of intersection. What is it you want to do?

John

My calculator said it, I believe it, that settles it

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