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Solve the system : x + y + z = 6, 2x - y + z = 3, x + y - z = 0
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x + y + z = 6, (1)
2x - y + z = 3, (2)
x + y - z = 0 (3)
Add equations (2) and (3) (both sides). You will get
3x = 3. Hence, x = 1.
Substitute x = 1 into equations ((1) and (3). You will get
1 + y + z = 6,
1 + y - z = 0,
or, which is the same,
y + z = 5, (3)
y - z = -1. (4)
Now add the equations (3) and (4) (both sides). You will get
2y = 4. Hence, y = 2.
Now from (3) z = 5 - y = 5 - 2 = 3.
Answer. x = 1, y = 2, z = 3.