SOLUTION: If I could please be helped, I'd be very thankful! I need help on finding the solution to a system of equations by substitution. The question Equation is: p=q+5 4p+5q=-34

Question 1033700: If I could please be helped, I'd be very thankful! I need help on finding the solution to a system of equations by substitution. The question
Equation is:
p=q+5
4p+5q=-34
Found 2 solutions by stanbon, Alan3354:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
p=q+5
4p+5q=-34
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Substitute for "p" and solve for "q"::
4(q+5) + 5q = -34
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4q + 20 + 5q = -34
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9q = -54
--------
q = -6
-----
Solve for "p"::
p = q+5
p = -6+5 = -1
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Cheers,
Stan H.
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Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
p=q+5
4p+5q=-34
==========
Sub for p in the 2nd eqn.
4(q+5) + 5q = -34
etc
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