SOLUTION: 4x^2+3y^2=4 2x-2y^2=-3

Question 1032302: 4x^2+3y^2=4
2x-2y^2=-3
Answer by ikleyn(52795) (Show Source): You can put this solution on YOUR website!
.

4x^2 + 3y^2 =  4,    (1)
2x   - 2y^2 = -3.    (2)

From (2), express 2x = . Now, substitute it into (1) by noting that  = . You will get a single equation for :

 +  = 4.

Open parentheses, collect the like terms and introduce the new variable z = .

Solve the obtained quadratic equation for z.

Then find "y" from z = .

Then find "x" from (2).

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