SOLUTION: 2x+y+z=12 3x+2y+3z=24 x+4y+9z=34

SOLUTION: 2x+y+z=12 3x+2y+3z=24 x+4y+9z=34

Algebra.Com

Question 1024070: 2x+y+z=12
3x+2y+3z=24
x+4y+9z=34
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Use Cramer's rule,

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So then,

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