SOLUTION: PLease help and show all work and answers because the answers I get is wrong. I do not know what I'm doing wrong. It been over 20 years so maybe that's the problem. Thanks for your

Question 1003011: PLease help and show all work and answers because the answers I get is wrong. I do not know what I'm doing wrong. It been over 20 years so maybe that's the problem. Thanks for your help.

Use the elimination method to find all solutions of the system
{x^2+y^2=5
x^2−y^2=1
The four solutions of the system are:
the one with x<0,y<0 is
x=
y=
the one with x<0,y>0 is
x=
y=
the one with x>0,y<0 is
x=
y=
the one with x>0,y>0 is
x=
y=
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Use the elimination method to find all solutions of the system
x^2 + y^2 = 5
x^2 - y^2 = 1
---------------Adding eliminates y^2, find x
2x^2 = 6
Divide both sides by 2
x^2 = 3
x = +
and
x = -
we know that x^2 = 3, substitute 3 for x^2 in the first equation
3 + y^2 = 5
y^2 = 5 - 3
y^2 = 2
y = +
and
y = -
:
The four solutions of the system are:
the one with x<0,y<0 is
x=-
y=-
the one with x<0,y>0 is
x=-
y=+
the one with x>0,y<0 is
x=+
y=-
the one with x>0,y>0 is
x =
y =

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