Some algebraic equations of high degree can be solved by reduction to the quadratic equation.
Below are examples of three forms of such equations.
Note that lessons explaining how to solve quadratic equations are
PROOF of quadratic formula...,
Introduction into quadratic equations and
Solving quadratic equations without quadratic formula of the module
Quadratic equations.
Example 1.
Solve an equation

.
Polynomial

can be factored into the product of

and

.
Solve an equation

first. It has two equal roots:

.
Then solve an equation

. It has roots

,

.
Thus, roots of the original equation are

,

,

.
Example 2.
Solve an equation

.
Let's rewrite this equation as

.
One root is

. Factor left side of

into the product of

and the polynomial of degree 2

, so

.
Solve an equation

using quadratic formula. The two roots are complex numbers

and

.
Thus, roots of the original equation are

,

and

.
Example 3.
Solve an equation

.
Let's introduce new variable

. Then the equation takes the form

.
This is the quadratic equation. It has two roots

,

.
Now solve an equation

. The roots of this equation are

and

.
Then solve an equation

. The roots of this equation are

and

.
So, the roots of the original equation are

,

,

and

.
Equations of this form are called
bi-quadratic equations.
Example 4.
Solve an equation

.
Let's introduce new variable

. Then the equation takes the form

.
This is the quadratic equation. It has two equal roots

.
Now solve an equation

. It has three roots

,

and

(see
Example 2).
They are solutions of the original equation.
Other three roots of the original equation are equal to these three (because

).
Method of
Example 1 can be extended to solve equations of the form

.
Method of
Example 2 can be extended to solve equations of the form

.
Method of
Example 3 can be extended to solve equations of the form

.
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