# SOLUTION: If f(x)= 1/3x^3 + 1/3x^2 + 1/3x + 1/3 and g(x)= x^2 + 1/3x + 1 calculate final answers as rational (fraction) numbers reduced to the lowest terms. PLEASE HELP...THIS PROBLEM

Algebra ->  -> SOLUTION: If f(x)= 1/3x^3 + 1/3x^2 + 1/3x + 1/3 and g(x)= x^2 + 1/3x + 1 calculate final answers as rational (fraction) numbers reduced to the lowest terms. PLEASE HELP...THIS PROBLEM       Log On

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 Question 64214: If f(x)= 1/3x^3 + 1/3x^2 + 1/3x + 1/3 and g(x)= x^2 + 1/3x + 1 calculate final answers as rational (fraction) numbers reduced to the lowest terms. PLEASE HELP...THIS PROBLEM IS VERY CONFUSING. I WOULD APPRECIATE IT A LOT! Answer by stanbon(60771)   (Show Source): You can put this solution on YOUR website!If f(x)= 1/3x^3 + 1/3x^2 + 1/3x + 1/3 and g(x)= x^2 + 1/3x + 1 calculate final answers as rational (fraction) numbers reduced to the lowest terms. ------------------------ f(x)= 1/3x^3 + 1/3x^2 + 1/3x + 1/3 If I assume the x-factors are in the denominator I get: A least common denominator of 2x^3. Then f(x)=1/lcd +x/lcd + x^2/lcd +x^3/lcd Rewrite to get: f(x)=[1+x+x^2+x^3]/3x^3 ----------------- g(x)= x^2 + 1/3x + 1 lcd=3x g(x)= 3x^3/lcd + 1/lcd + 3x/lcd g(x)=[3x^3+1+3x]/3x ---------- Cheers, Stan H.