# SOLUTION: Use the system to answer the question {x+3y=6} {4x + 6y = -6} Note: The problem above are both under the { symbol, the first one is over the second one. These are the ch

Algebra ->  -> SOLUTION: Use the system to answer the question {x+3y=6} {4x + 6y = -6} Note: The problem above are both under the { symbol, the first one is over the second one. These are the ch      Log On

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 Question 565619: Use the system to answer the question {x+3y=6} {4x + 6y = -6} Note: The problem above are both under the { symbol, the first one is over the second one. These are the choices for the problem (-9, 5) (-3, 3) (6, 3) (12, -2) I'm not sure how I got it wrong. The correct answer was the first one. (I have the answers, so I can redo the ones I missed, but I have to show my work, and I don't know how to get that answer.) Could you look over my work that I did and explain how to get the solution? Thanks, much appreciated. My Work: {x+3y=6} {4x + 6y = -6} 1. I multiply the first equation by -4 so I can eliminate the 4x (-4) {x+3y=6} + {-4x -12y = -24} 2. I eliminate the 4x from the problem {-4x - 12y = -24} {4x + 6y = -6} (-4 and 4 crosses out so I'm left with" 0x - 12y = -24 0x + 6y = -6 3. Then I solve: -12 and a + 6 gets a -6. -24 and -6 gets -18 so I get 0x -6y = -18 From there I am stuck. I'm not sure if I use substitution or elimination or what. Thanks for your help! Answer by stanbon(60771)   (Show Source): You can put this solution on YOUR website!{x+3y=6} {4x + 6y = -6} ---------------- Multiply thru the 1st equation by 2: 2x + 6y = 12 4x + 6y = -6 ---------------------- Subtract and solve for "x": 2x = -18 x = -9 --------------- Solve for "y": x + 3y = 6 -9 + 3y = 6 3y = 15 y = 5 ------------------- Solution: (-9,5) ==================== Cheers, Stan H. These are the choices for the problem (-9, 5) (-3, 3) (6, 3) (12, -2)