Tutors Answer Your Questions about Surface-area (FREE)
Question 123789: Hi, I have hard time picturing the word problem in my head. Could you please help me solving it?
Marcos wants to make an open box by cutting equal squares from each corner of a rectangular piece of cardboard measuring 12 by 20 inches. If the box needs a base of 84 sq. inches, what size square should be cut from each corner?
Thank you very much!
Click here to see answer by ilana(307) |
Question 124026: I have a castle Length is 19ft width is 18ft. Across the top are parapets whose L=3 and W=2. There are 4 of them. On the bottom is a door. The L=4 and W=6. I took the 4 parapets and got their total area as 36ft. The base of the castle is 288ft. The area of the door is 24ft. Now how I got the bases area is by subtracting the 3ft of the end parapet to get a L of 16ft. So it goes like this BASE 16ftX18ft=288ft. Parapets 9ftX 4=36ft. DOOR 4ft X 6ft=24ft.
So. Base + Parapets - Door = 300sqft. Is this right?
Click here to see answer by amal(1) |
Question 127042: The reason for this being here is that the answer that you get is the area of a square.
I have a problem that I just can't figure out.
Find the sum of the folowing to 3 decimal spaces on your calculator and explain the sequence of keys used to arrive at your answer.
7over
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3sqrt5 + sqrt2
I really appreiciate your help.
Kindest regards.
Click here to see answer by stanbon(57203) |
Question 128413: A formula for the total surface area of a cylinder is given as: T = 2(pi)r(h+r), where h is the altitude and r is the radius of a base. Find the altitude in centimeters if the radius = 6cm and the total surface area = 168(pi)cm^2.
I need help in knowing how to set this up and solving it. thank you
Click here to see answer by josmiceli(9645)  |
Question 128529:
A kitchen floor measures 12ft 8in wide by 18ft 9in long. The floor is being covered with tiles that are 8 inch square. How many titles must be bought to cover the floor..
12.8 X 18.9 = 241.92/8 = 30.24
31 titles are needed
Click here to see answer by checkley71(8403) |
Question 128812: To approach the runway, a small plane must begin a 9 degree descent starting from a height of 1125 feet above the ground. To the nearest tenth of a mile, how many miles from the runway is the airplane at the start of this approach?
This picture on the paper has a right triangle with 1125 as its height and nothing on the base next to the 90 degree is 9 degrees in the corner and an x as the hypotenuse.
Click here to see answer by stanbon(57203) |
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