SOLUTION: How much square feet of surface area is in a cylinder 48' high and 80' diameter

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Question 98977: How much square feet of surface area is in a cylinder 48' high and 80' diameter
Found 2 solutions by jim_thompson5910, checkley71:
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Since the diameter is 80', the radius is 40' (which is half of the diameter)


Solved by pluggable solver: Surface area and Volume of a cylinder
The surface area (SA) of a cylinder, excluding the base area and top area, is given by


When the areas of base and top are included, the surface area becomes



The volume of the cone can be found by the formula



In our case the desired values are thus:

SA (without base and top) =
SA (with base and top) =
V =


For more on this topic, refer to Surface area and Volume.

Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!
TSA=(PI*D)H+2(PI*R^2)
TSA=3.14*80+2(3.14*40^2)
TSA=2512+2*5024
TSA=2512+10048
TSA=12560 IS THE TOTAL SURFACE AREA OF THIS CYLINDER.

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