SOLUTION: here is a problem given to me today i really don't know how to solve this problem. no.1 question how much paper is needed to wrap a box of 54cm long, 45 cm wide and 28 cm high?

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Question 95994: here is a problem given to me today i really don't know how to solve this problem.
no.1 question
how much paper is needed to wrap a box of 54cm long, 45 cm wide and 28 cm high?
no.2 question
a box in the shape of a rectangular prism has a lenght of 0.5m, a width of 0.4m and a height of 0.3m.can all the sides of the box with 4m^2 of contact paper?how much contact paper will be left over or needed?
no.3 question
rodel candiente estimates that a large building has 330m^2 of area to be painted a can of paint covers about 15m^2 and costs 459.90 pesos.what will be the cost of the paint for the building?
Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website!
p=perimeter l=length w=width h=height
p(top or bottom)=2(l+w)=2(54+45)=198
p(1 of 4 sides)=2(h+l)=2(28+54)=164
So 2(198)+4(164)=perimeter of the entire box
396+656=1052 cm of paper
no.2 is similar to no.1. You should be able to do that now.
no.3 we set up a proportion with cost on the left side of the equal sign and area to be painted on the right

multiply 459.90 times both sides.=10,117.80 pesos
EdJones