My diagram shoes two squares.The sum of their area is 58m2.The sum of the lengths of their side is10m..Find values for x and y(y >x)..no idea how to go about this..Thanks
One side of 1st square: x
Area of 1st square:
One side of 2nd square: y
Area of 2nd square:
Sum of their areas is , so: ------ eq (i)
Sum of the lengths of a side of each square is 10, so: x + y = 10____y = 10 - x ------ eq (ii)
------- Substituting 10 - x for y in eq (i)
(x - 7)(x - 3) = 0
OR
If x = 7, then y = 3
If x = 3, then y = 7
However, since y > x, then the latter is the correct choice.