SOLUTION: The length of a rectangle is 1 cm more than 5 times its width. If the area of the rectangle is 89 cm2, find the dimensions of the rectangle to the nearest thousandth. I wonder

Question 91310: The length of a rectangle is 1 cm more than 5 times its width. If the area of the rectangle is 89 cm2, find the dimensions of the rectangle to the nearest thousandth.
I wonder if this is somewhat on track? I have been baffled for the past three hours,on this equation.
(1+2x)(5+2x)=89
3+-the square root of 93/2
the square root of 93 divided by 2=9.64divided by 2=4.862182 plus three=7.82182
and 4.862182-3=1.82182
Answer by tutor_paul(519) (Show Source): You can put this solution on YOUR website!
Write an equation for the length in terms of width:
Equation #1:
Write an expression for the Area:
Equation #2:
Now you have 2 equations with 2 unknowns. Any time you have at lease as many equations as you have unknowns, you can find the unknowns!
===================================
Substitute the value of L from Equation #1 into Equation #2:

Apply the quadratic formula:

W=(-1+-42.2)/10
W=4.12,W=-4.32
The width needs to be positive, so throw out the negative result:

Now, substitute this value of W into Equation #1 to find L.
I will leave that part to you :-)
Goos Luck,
tutor_paul@yahoo.com

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