SOLUTION: one square has side length s and another square has side length 2s. what is the ratio of the larger square to the area of the smaller square? justify your answer
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Question 897233: one square has side length s and another square has side length 2s. what is the ratio of the larger square to the area of the smaller square? justify your answer
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Area1 = s^2
Area2 = (2s)^2 = 4s^2
ratio of 4:1
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