SOLUTION: how do i figure out the surface area of half a cylinder Diameter:45 H:12

Question 857299: how do i figure out the surface area of half a cylinder Diameter:45 H:12
Found 2 solutions by rothauserc, sexybitch:
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
surface area of cylinder(SA) = 2*pi*r^2 + 2*pi*r*h
therefore half the SA of a cylinder is
SA = 1/2(2*pi*r^2 + 2*pi*r*h)
SA = 1/2(2*pi*(22.5)^2) + (2*pi*(22.5)*12)
SA = 1/2(3180.86 + 1696.46) = 2438.66

Answer by sexybitch(2) (Show Source): You can put this solution on YOUR website!
the surface area of cylinder(SA) = 2*pi*r^2 + 2*pi*r*h
therefore half the SA of a cylinder is
SA = 1/2(2*pi*r^2 + 2*pi*r*h)
SA = 1/2(2*pi*(22.5)^2) + (2*pi*(22.5)*12)
SA = 1/2(3180.86 + 1696.46) = 2438.66
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