SOLUTION: step 1: 30/π∫ max: 2 min: 0) (π/6)*sec((πx)/6)dx = 30/π(ln|sec((xπ)/6)+tan((xπi)/6)|] (max: 2 min: 0)
step 2: = 30/π(ln|sec((π)/__
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Question 838142: step 1: 30/π∫ max: 2 min: 0) (π/6)*sec((πx)/6)dx = 30/π(ln|sec((xπ)/6)+tan((xπi)/6)|] (max: 2 min: 0)
step 2: = 30/π(ln|sec((π)/__?__)+tan((π)/__?__)| - ln|1+0|]
step 3: = (30/π)ln(__?__+sqrt(__?__))
step 4: = __?__ (rounded to three decimal places)
step 5: Thus the area of the bounded region is approximately __?__ (rounded to three decimal places).
Can you please tell me what to put where it reads __?__
Answer by KMST(5328) (Show Source): You can put this solution on YOUR website!
Apparently you are integrating the function
to find the area under the curve between and .
step 1:
The antiderivative or indefinite integral of the function
is the function
The definite integral between the limits and is calculated as
.
For , so
For , so
step 2: =
, , and , so (rounded to three decimal places).
step 3: =
My calculator says that
step 4: =
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