SOLUTION: Hi,
I know that the area of a triangle is 1/2 bh but that is not one of the answers.
How can I find the area in this triangle?
Thanks.
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Question 823989: Hi,
I know that the area of a triangle is 1/2 bh but that is not one of the answers.
How can I find the area in this triangle?
Thanks.
Found 2 solutions by Alan3354, jim_thompson5910:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
h = a*sin(t)
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Rule:
Area of Triangle = (Base)*(Height)/2
Note: the base and height are ALWAYS perpendicular segments
Since h is the height (given and fixed), this forces us to choose b as the base since b is perpendicular to h
So....
Area of Triangle = (Base)*(Height)/2
A = b*h/2
-------------------------------------------------------
Now focus on the smaller triangle on the left (with hypotenuse 'a' and leg 'h')
sin(angle) = opposite/hypotenuse
sin(theta) = h/a
a*sin(theta) = h
h = a*sin(theta)
-------------------------------------------------------
Now go back to the area of a triangle equation and plug h = a*sin(theta) in
A = b*h/2
A = (1/2)*b*h
A = (1/2)*b*(a*sin(theta))
A = (1/2)ab*sin(theta)
So the answer is choice D
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