SOLUTION: Find the volume in terms of pi of a sphere whose surface area is {{{36*pi^2}}}. The formula for the volume of a sphere is {{{ V=(4/3)*(pi)*r^3}}} and for the surface area of a sphe

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Question 76989This question is from textbook PRENTICE HALL MATHEMATICS GEOMETRY
: Find the volume in terms of pi of a sphere whose surface area is . The formula for the volume of a sphere is and for the surface area of a sphere is This question is from textbook PRENTICE HALL MATHEMATICS GEOMETRY

Answer by bucky(2189)   (Show Source): You can put this solution on YOUR website!
I've taken the liberty of changing the problem a little to add the correct formula for the
Surface Area (call it S) of a sphere. This formula is
.
You are told that for a particular sphere, the surface area is . Substitute
this value into the surface area equation in place of S and you get:
.

.
What we are going to do now is solve this equation for r. Begin by dividing both sides of
the equation by 4. When you do that the equation reduces to:
.

.
Next divide both sides of the equation by . This further reduces the equation to:
.

.
Since we're going to solve for r, let's transpose the equation (switch left and right sides)
to get it into the more conventional form:
.

.
Now you can solve for r by taking the square root of both sides. When you do that you
get:
.

.
We now know what the radius of the given sphere is. To find the volume (V) of this sphere
we substitute this value for the radius into the volume equation. The volume equation is:
.

.
substitute for the radius in the volume equation and you get:
.

.
By the rules of exponents, when you cube a factored quantity, it is equivalent to cubing
each of the individual factors. Therefore, .
But and
.
Substitute these values into the volume equation and you get:
.

.
But some of the factors on the right side can be multiplied into a simpler form. The product
of is 36 and the product of is . Substituting
these into the volume equation results in:
.

.
For the given sphere whose surface area is the volume is:
.

.
Hope this helps you to understand the relationship between the surface area and volume
equations for a given sphere.

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