SOLUTION: Find the area of the region in the xy - plane under the line y = x/2 above the x-axis, and between the lines x=8 and x=24 . find area?
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Question 763107: Find the area of the region in the xy - plane under the line y = x/2 above the x-axis, and between the lines x=8 and x=24 . find area?
Found 3 solutions by Alan3354, josgarithmetic, MathLover1:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Find the area of the region in the xy - plane under the line y = x/2 above the x-axis, and between the lines x=8 and x=24
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That makes a rectangle and a right triangle.
The rectangle is 16 by 4.
The triangle's base is 16 and its height is 8.
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
TRAPEZOID! Base is and average height is
Area is {base*AverageHeight}
square units.
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
Find the area of the region in the - plane under the line above the , and between the lines and
the region in the xy - plane is right-angular trapezoid and its area is:
in this case , , and because if then
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