SOLUTION: Find the area of the region enclosed by y=2x^2 and y=8x-6

Question 753489: Find the area of the region enclosed by y=2x^2 and y=8x-6
Answer by Cromlix(4381) (Show Source): You can put this solution on YOUR website!
2x^2= 8x - 6
2x^2 - 8x + 6
(2x - 2)(x - 3)
x = 1, 3
Integrate 2x^2 - 8x + 6
[ 2x^3/3 - 4x^2 + 6x]
Using x=1 and x = 3
(2*3^3/3 - 4*3^2 + 6*3)-(2*1^3/3 - 4*1^2 + 6*1)
(54/3 - 36 + 18) - (2/3 - 4 + 6)
(54/3 - 54/3) - (2/3 + 6/3)
- 8/3 units^2
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