SOLUTION: Mark has a rectangular cardboard of length 68 cm and perimeter 230cm. He cuts a part of the cardboard to make a cubical box 12cm long. What is the area of the cardboard left?
Algebra.Com
Question 699221: Mark has a rectangular cardboard of length 68 cm and perimeter 230cm. He cuts a part of the cardboard to make a cubical box 12cm long. What is the area of the cardboard left?
Answer by pmatei(79) (Show Source): You can put this solution on YOUR website!
To find the area of the cardboard left, you need to know how much area you had and how much area you cut.
The rectangle area is length times width. We know the length and perimeter which is 2 lengths and 2 widths.
So the area of the rectangle is:
Now lets calculate the area you cut for the cubical box. If the box does not have a lid, then you need 5 squares of side 12 cm. If the box has a lid, then you have a complete cube and you need 6 squares.
I assume it is a box without lid. Then the area is:
Thus the remaining area after I cut enough for the box is:
square cm.
RELATED QUESTIONS
A rectangular piece of cardboard measures 18 cm by 15 cm. What is the perimeter of the... (answered by rfer)
Algebra
the perimeter of a square is 220 feeT? what is the length of each side?
2. (answered by checkley77)
Lorene plans to make a box from rectangular sheets of cardboard from which she cuts out 6 (answered by ankor@dixie-net.com)
Mathew cuts four right angled triangles from the corners of a square cardboard. What is... (answered by macston)
A rectangular sheet of cardboard was used to make a pencil box. Four (4) small squares... (answered by josgarithmetic)
A rectangular piece of cardboard has an area of 256 square centimeters. The length of the (answered by ikleyn)
A rectangular sheet of cardboard has a square of the same size cut from each of its... (answered by ankor@dixie-net.com)
Mary wants to make a box. She starts with a piece of cardboard who's the length is 15 cm (answered by josgarithmetic)
(APPLIED PROBLEM) What is the equation and solution:
A rectangular cardboard is to be... (answered by ankor@dixie-net.com)