SOLUTION: what is the area of a square whose side measures 2s+5
Algebra.Com
Question 685936: what is the area of a square whose side measures 2s+5
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
A = x^2
A = (2s+5)^2
A = (2s+5)(2s+5)
A = 2s(2s+5)+5(2s+5)
A = 4s^2+10s+10s+25
A = 4s^2+20s+25
So the area is 4s^2+20s+25 square units.
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