SOLUTION: What is the awnser to this question?: l=12inches, w=4inches? Lenght and with. I have to find the perimeter and the area of the rectangle or square with the given demensions. Explai
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Question 554724: What is the awnser to this question?: l=12inches, w=4inches? Lenght and with. I have to find the perimeter and the area of the rectangle or square with the given demensions. Explain how u got it please.
Found 2 solutions by jim_thompson5910, nyc_function:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Area:
A = LW
A = 12*4
A = 48
Area is 48 square inches.
-------------------------------------------------------
Perimeter
P = 2L + 2W
P = 2(12)+2(4)
P = 24+8
P = 32
Perimeter is 32 inches.
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Answer by nyc_function(2741) (Show Source): You can put this solution on YOUR website!
Use the following two formulas:
For area use: A = Length times width
For perimeter use: P = 2(length) + 2(width)
L = 12, W = 4
A = 12 times 4
A = 48in^2
The area is 48 squared inches.
==============================
P = 2(12) + 2(4)
P = 24 + 8
P = 32 inches
The perimeter is 32 inches.
The figure given is a rectangle not a square.
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