# SOLUTION: The safe load a beam can support varies jointly as the width and the square of the depth and inversely as the length. If a 2 x 8 inch beam 16 feet long is turned so that the width

Algebra ->  Surface-area -> SOLUTION: The safe load a beam can support varies jointly as the width and the square of the depth and inversely as the length. If a 2 x 8 inch beam 16 feet long is turned so that the width       Log On

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 Question 507544: The safe load a beam can support varies jointly as the width and the square of the depth and inversely as the length. If a 2 x 8 inch beam 16 feet long is turned so that the width is 2 inches, it can support 2,000 pounds. How much weight can the same bea, support if it is turned so that the width is 8 inches? Answer by Earlsdon(6294)   (Show Source): You can put this solution on YOUR website!First write the equation of proportionality: To find the value of k, the constant of proportionality, substitute the given values of: L = 2000, w = 2, d = 8, and l = 16 Solve for k. Multiply both sides by 16. Divide by 128. so we can rewrite the first equation as: Now we can find the safe load, L, for the given parameters: w = 8, d = 2, and l = 16. pounds.