SOLUTION: The safe load a beam can support varies jointly as the width and the square of the depth and inversely as the length. If a 2 x 8 inch beam 16 feet long is turned so that the width

Question 507544: The safe load a beam can support varies jointly as the width and the square of the depth and inversely as the length. If a 2 x 8 inch beam 16 feet long is turned so that the width is 2 inches, it can support 2,000 pounds. How much weight can the same bea, support if it is turned so that the width is 8 inches?

Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
First write the equation of proportionality:
To find the value of k, the constant of proportionality, substitute the given values of: L = 2000, w = 2, d = 8, and l = 16
Solve for k. Multiply both sides by 16.
Divide by 128.
so we can rewrite the first equation as:
Now we can find the safe load, L, for the given parameters: w = 8, d = 2, and l = 16.

pounds.
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