SOLUTION: A circular target with a radius of 5 centimeters has a circular bull's eye with a diameter of 2 centimeters. Darts are thrown and hit the target at random. A)What is the pr

Question 33490: A circular target with a radius of 5 centimeters has a circular bull's eye with a diameter of 2 centimeters. Darts are thrown and hit the target at random.
A)What is the probability that a dart will hit the bull's eye?
B)Estimate how many times a dart will hit the bull's eye if 100 darts are thrown and hit the target at random.
I found that the area of the entire target is 78.5 and the area of the bull's eye is 12.56 and I think that it may have to be put in a proportion but I am stumped and have no clue what to do. Could someone explain it to me.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Good. If your area figures are correct the probability of
hitting the bullseye is 12.56/78.5=0.16
The expected value is np where n=100 and p=0.16
So the expected number of hits is 16 out of 100.
RELATED QUESTIONS
A regular hexagonal shaped target with sides of length 14 centimeters has a circular... (answered by solver91311)

I have a hexagon and its side lengths are of 14cm, and it has a circular bulls eye right... (answered by fractalier)

A circular target has a radius of 25 cm. What is the probability of hitting a 1 cm... (answered by stanbon)

I have a hexagon and its side lengths are of 14cm, and it has a circular bulls eye right (answered by Boreal)

Please answer this, thanks. What is the approximate volume of a right circular cone,... (answered by rfer,rammi123)

How tall must you construct a right circular cylinder with a radius of 3 centimeters to... (answered by Fombitz)

An engineer creates a model using a right circular cylinder with a diameter of 5... (answered by Alan3354)

A store sells ice cream either in biscuit cones with diameter 6 centimeters and height H... (answered by josgarithmetic)

A circular target has a radius of 25cm. What is the probability of hitting a 1cm diameter (answered by Fombitz)