SOLUTION: A rectangle has an area given by A=-6w^2+72w . What is the maximum area for this rectangle? (Hint: Where does the maximum value occur?)

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Question 322121: A rectangle has an area given by A=-6w^2+72w . What is the maximum area for this rectangle? (Hint: Where does the maximum value occur?)
Answer by JBarnum(2146)   (Show Source): You can put this solution on YOUR website!
review explaination below
w=-0,12




thruogh guess and check doing the quadratic formula several times with different amouts i came to find the following:
if A=217 then it is an imaginary answer so A has to equal 216 as its maximum
216=-6w^2+72w
0=-6w^2+72w-216
W=6
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=5184 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 0, 12. Here's your graph:
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