SOLUTION: Find the area of a regular hexagon with side length 6m. Round to the nearest tenth. sin 30 degrees= .5000 cos 30 degrees= .8660 tan 30 degrees= .5774

Algebra ->  Algebra  -> Surface-area -> SOLUTION: Find the area of a regular hexagon with side length 6m. Round to the nearest tenth. sin 30 degrees= .5000 cos 30 degrees= .8660 tan 30 degrees= .5774      Log On

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Question 309508: Find the area of a regular hexagon with side length 6m. Round to the nearest tenth.
sin 30 degrees= .5000
cos 30 degrees= .8660
tan 30 degrees= .5774
Answer by Alan3354(30993) About Me  (Show Source):
You can put this solution on YOUR website!
Find the area of a regular hexagon with side length 6m. Round to the nearest tenth.
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The area of any regular polygon with n sides of length s is:
Area+=+n%2As%5E2%2Acot%28180%2Fn%29%2F4+=+6%2A6%5E2%2Acot%2830%29%2F4
= 54cot(30)
=~ 93.5 sq meters
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