# SOLUTION: It says the outside dimensions of a picture frame are 4 feet by 29 inches.If its inside dimensions are 1 3/4 feet by 21 inches what is the area of the frame? I dont understand w

Algebra ->  Algebra  -> Surface-area -> SOLUTION: It says the outside dimensions of a picture frame are 4 feet by 29 inches.If its inside dimensions are 1 3/4 feet by 21 inches what is the area of the frame? I dont understand w      Log On

 Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Geometry: Area and Surface Area Solvers Lessons Answers archive Quiz In Depth

 Question 277623: It says the outside dimensions of a picture frame are 4 feet by 29 inches.If its inside dimensions are 1 3/4 feet by 21 inches what is the area of the frame? I dont understand where to start HELP?!?!Answer by mananth(12270)   (Show Source): You can put this solution on YOUR website!It says the outside dimensions of a picture frame are 4 feet by 29 inches.If its inside dimensions are 1 3/4 feet by 21 inches what is the area of the frame? I dont understand where to start HELP?!?! 4feet = 48 inches Outside area = 48*29= 1392 square inches 1 3/4 feet = 21 inches Indise area = 21 *21 =441 sq. inches Difference between the outer area and the inner area will give the area of the frame 1392-441=951 square inches