SOLUTION: A can of vegetables has a diameter of 9.8 cm and is 13.2 cm tall. How much paper is required to make the label, assuming there is no overlap?

Question 263028: A can of vegetables has a diameter of 9.8 cm and is 13.2 cm tall. How much paper is required to make the label, assuming there is no overlap?
Found 2 solutions by mananth, georgiabh:
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!

surface area of cylinder
area = pi*d*h
22/7*9.8*13.2
406.56 sq. cms.of paper is required.

Answer by georgiabh(4) (Show Source): You can put this solution on YOUR website!
You need to find the surface area of the sides of the can.
Imagine that this label, before being wrapped around the can would actually be a rectangle.
The area of a rectangle is its' height x width.
The height is 13.2 cm.
The width is the the length of the paper going around the can which is the circumference of the can.
The circumference of a circle is given by the equation pi x D where D is the diameter of the can which is pi x 9.8
So the answer is pi x 9.8 x 13.2
So the area of the paper required is 406.4 cm sq.
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