SOLUTION: What is the area under the graph of the function f(t)= t^8+t between t=0 and t=1?

Question 255563: What is the area under the graph of the function f(t)= t^8+t between t=0 and t=1?

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
What is the area under the graph of the function f(t)= t^8+t between t=0 and t=1?
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I assumne you mean area under the graph and above the t-axis.
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Ans:
int from 0 to 1 of t^8+t
(1/9)t^9 + (1/2)t^2 evaluated at t = 1 minus the evaluation when t = 0.
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= (1/9)(1^9)+(1/2)(1^2) - [(1/9)*0^9 + (1/2)*0^2]
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= (1/9) + (1/2)
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= 11/18 sq. units
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Cheers,
Stan H.
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