SOLUTION: find the dimensions of the rectangle meeting the specified conditions the perimeter is 320 cm and the width is 20 cm less than the length

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Question 223776: find the dimensions of the rectangle meeting the specified conditions
the perimeter is 320 cm and the width is 20 cm less than the length

Found 2 solutions by stanbon, drj:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
find the dimensions of the rectangle meeting the specified conditions
the perimeter is 320 cm and the width is 20 cm less than the length
----------------------
Perimeter = 2(L + W)
320 = 2(L + (L-20))
160 = 2L-20
2L = 180
L = 90 cm (length)
W = L-20 = 70 cm (width)
=========================
Cheers,
Stan H.

Answer by drj(1380)   (Show Source): You can put this solution on YOUR website!
Find the dimensions of the rectangle meeting the specified conditions
the perimeter is 320 cm and the width is 20 cm less than the length

Step 1. Let L be the length

Step 2. Let L-20 be the width since it's 20 cm less than the length

Step 3. Perimeter P means adding up all 4 sides of the rectangle.

Step 4. Then, P=L+L+L-20+L-20=320 since perimeter is 320 cm.

Solved by pluggable solver: EXPLAIN simplification of an expression
Your Result:


YOUR ANSWER


  • This is an equation! Solutions: L=90.
  • Graphical form: Equation was fully solved.
  • Text form: L+L+L-20+L-20=320 simplifies to 0=0
  • Cartoon (animation) form:
    For tutors: simplify_cartoon( L+L+L-20+L-20=320 )
  • If you have a website, here's a link to this solution.

DETAILED EXPLANATION


Look at .
Added fractions or integers together
It becomes .

Look at .
Moved -40 to the right of expression
It becomes .

Look at .
Removed extra sign in front of -40
It becomes .

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Eliminated similar terms highlight_red%28+L+%29,highlight_red%28+L+%29,highlight_red%28+L+%29,highlight_red%28+L+%29 replacing them with highlight_green%28+%281%2B1%2B1%2B1%29%2AL+%29
It becomes .

Look at .
Added fractions or integers together
It becomes .

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Remove unneeded parentheses around factor highlight_red%28+4+%29
It becomes .

Look at .
Moved these terms to the left highlight_green%28+-320+%29
It becomes .

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Added fractions or integers together
It becomes .

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Removed extra sign in front of -360
It becomes .

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Solved linear equation highlight_red%28+4%2AL-360=0+%29 equivalent to 4*L-360 =0
It becomes .
Result:
This is an equation! Solutions: L=90.

Universal Simplifier and Solver


Done!



With and L-20=70}}}. Also which is a true statement.

Step 5. The dimensions are that the length is 90 cm and the width is 70 cm.

I hope the above steps were helpful.

For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.

And good luck in your studies!

Respectfully,
Dr J

drjctu@gmail.com

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