Step 1. Let n be one positive integer and n+1 is the next consecutive positive
number
Step 2. n(n+1) be the product between these positive integers.
Step 3. n+n+1=2n+1 be the sum of the two positive integers.
Step 4. Then using Steps 2, 3 and the problem statement yields, n*(n+1)=2n+1+29
Step 5. The following steps will solve the equation in Step 4.
| Solved by pluggable solver: EXPLAIN simplification of an expression | |
Your Result: YOUR ANSWERDETAILED EXPLANATIONLook at Added fractions or integers together It becomes Look at Moved these terms to the left It becomes Look at Expanded term It becomes Look at Remove extraneous '1' from product It becomes Look at Reduce similar several occurrences of It becomes Look at Eliminated similar terms It becomes Look at Added fractions or integers together It becomes Look at Removed extra sign in front of It becomes Look at Remove unneeded parentheses around factor It becomes Look at Remove extraneous '1' from product It becomes Look at Equation It becomes Result: This is an equation! Solutions: n=6,n=-5. Universal Simplifier and SolverDone! |
Step 6. Select the positive solution and in this case it's n=6.
Step 7. So the integers are 6 and 7. Note: The product is 42 which is 29 more than their sum of 13.
I hope the above steps were helpful.
For free Step-By-Step Videos on Introduction to Algebra, please visit http://www.FreedomUniversity.TV/courses/IntroAlgebra or for Trigonometry visit http://www.FreedomUniversity.TV/courses/Trigonometry.
And good luck in your studies!
Respectfully,
Dr J