SOLUTION: The length of a rectangle is six times its width. If the area of the rectangle is 150 yd 2 , find its perimeter.

Algebra.Com
Question 202909: The length of a rectangle is six times its width. If the area of the rectangle is 150 yd 2 , find its perimeter.
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!


The perimeter of a rectangle is given by:



But if we let represent the width, then represents the width. Therefore the perimeter is:



Now all you need is the value of

The area of a rectangle is given by:

and we know the area is 150,

so



Solve for and multiply by 14.

John


RELATED QUESTIONS

The length of a rectangle is six times its width. If the perimeter of the rectangle is... (answered by mananth)
Please help me solve this equation: {{The length of a rectangle is six times its width. (answered by lwsshak3)
The length of a rectangle is six times its width. If the perimeter of the rectangle is (answered by macston)
the Length of a rectangle is four times its width. If the area of the rectangle is 324... (answered by nyc_function)
The length of a rectangle is 2 yd longer than its width. If the perimeter of... (answered by IBMath)
The length of a rectangle is six times its width. If the area of the rectangle is 150,... (answered by shree840)
The length of a rectangle is six times its width. If the area of the rectangle is 150 (answered by MathLover1)
The perimeter of a rectangle is 100 yd. If its width is four times its length, what is... (answered by josgarithmetic)
The length of a rectangle is three times its width. If the perimeter of the rectangle... (answered by Cromlix)