# SOLUTION: In rectangle ABCD, AB=6 and the length of diagonal AC is 10. The area of ABCD is 1.60 2.48 3.32 4.28

Algebra ->  Algebra  -> Surface-area -> SOLUTION: In rectangle ABCD, AB=6 and the length of diagonal AC is 10. The area of ABCD is 1.60 2.48 3.32 4.28      Log On

 Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help! Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations!

 Geometry: Area and Surface Area Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Surface-area Question 198416: In rectangle ABCD, AB=6 and the length of diagonal AC is 10. The area of ABCD is 1.60 2.48 3.32 4.28Answer by anantha(86)   (Show Source): You can put this solution on YOUR website!sol: in rectangle ABCD in which AC and BD are diagonals then AC^2+BD^2=AB^2+BC^2+CD^2+DA^2 PROOF: IN RIGHT ANGLED TRIANGLE ABC AC^2=AB^2+BC^2 (PYTHAGORAS THEOREM) IN RIGHT ANGLED TRIANGLEBDC BD^2=BC^2+CD^2 ADDING ABOVE EQUATIONS AC^2+BD^2=AB^2+BC^2+BC^2+CD^2 AC^2+BD=AB^2+BC^2+DA^2+CD^2 (BC=DA) in rectangle AB=DC=6 given,AD=BC=x taken,AC=BD=10 GIVEN substitute these values in the above formula 10^2+10^2=6^2+x^2+x^2+6^2 100+100=36+x^2+x^2+36 200=72+2x^2 2x^2=200-72 2x^2=128 x^2=64 x=sqrt(64)=8 AB=6 AND BC=8 Area of the rectangle=AB*BC=6*8=48